MHT CET · Physics · Ray Optics
For a light ray to undergo total internal reflection ( \(\mathrm{i}=\) angle of incidence, \(\mathrm{i}_{\mathrm{c}}=\) critical angle )
- A light travels from denser to rarer medium and \(\mathrm{i} \lt \mathrm{i}_{\mathrm{c}}\).
- B light travels from rarer to denser medium and \(\mathrm{i} \lt \mathrm{i}_{\mathrm{c}}\).
- C light travels from denser to rarer medium and \(\mathrm{i}\gt\mathrm{i}_{\mathrm{c}}\).
- D light travels from rarer to denser medium and \(\mathrm{i}\gt\mathrm{i}_{\mathrm{c}}\).
Answer & Solution
Correct Answer
(C) light travels from denser to rarer medium and \(\mathrm{i}\gt\mathrm{i}_{\mathrm{c}}\).
Step-by-step Solution
Detailed explanation
So in order for total internal reflection to take place; The rays of light must travel from a dense medium to a less dense medium. The angle of incidence must be greater than the critical angle.
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