MHT CET · Physics · Kinetic Theory of Gases
For a gas \(\frac{R}{c_{v}}=0 \cdot 67\). This gas is made up of molecules which are
- A diatomic.
- B polyatomic.
- C monoatomic.
- D mixture of diatomic and polyatomic.
Answer & Solution
Correct Answer
(C) monoatomic.
Step-by-step Solution
Detailed explanation
(C)
\(\frac{R}{C_{v}}=0.67\)
\(\therefore \mathrm{R}=0.67 \mathrm{C}_{\mathrm{v}}\)
\(\therefore C_{p}-C_{v}=0.67 \mathrm{C}_{v}\)
\(\therefore C_{p}=1.67 \mathrm{C}_{v}\)
\(\therefore \gamma=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}}=1.67\)
For a monoatomic gas \(\gamma=\frac{5}{3}\) or \(1.67\)
\(\frac{R}{C_{v}}=0.67\)
\(\therefore \mathrm{R}=0.67 \mathrm{C}_{\mathrm{v}}\)
\(\therefore C_{p}-C_{v}=0.67 \mathrm{C}_{v}\)
\(\therefore C_{p}=1.67 \mathrm{C}_{v}\)
\(\therefore \gamma=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}}=1.67\)
For a monoatomic gas \(\gamma=\frac{5}{3}\) or \(1.67\)
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