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MHT CET · Physics · Kinetic Theory of Gases

For a gas, \(\frac{\mathrm{R}}{\mathrm{C}_{\mathrm{V}}}=0 \cdot 4\) where 'R' is universal gas constant and \(\mathrm{C}_{\mathrm{V}}\) is the molar specific heat at constant volume. The gas is made up of molecules which are

  1. A polyatomic.
  2. B rigida diatonilc.
  3. C non-rigidd diatamịC.
  4. D monnatonic.
Verified Solution

Answer & Solution

Correct Answer

(B) rigida diatonilc.

Step-by-step Solution

Detailed explanation

\(
\begin{array}{l}
\frac{\mathrm{R}}{\mathrm{C}_{\mathrm{v}}}=0.4 \\
\mathrm{R}=0.4 \mathrm{C}_{\mathrm{v}} \\
\mathrm{C}_{\mathrm{p}}-\mathrm{C}_{\mathrm{v}}=\mathrm{R} \\
\mathrm{C}_{\mathrm{p}}=\mathrm{R}+\mathrm{C}_{\mathrm{v}}=(0.4+1) \mathrm{C}_{\mathrm{v}}=1.4 \mathrm{C}_{\mathrm{v}} \\
\therefore \frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}}=1.4=\mathrm{v}
\end{array}
\)
\(\therefore\) gas is made up of rigid diatomic molecules.
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