MHT CET · Physics · Kinetic Theory of Gases
For a gas, \(\frac{\mathrm{R}}{\mathrm{C}_{\mathrm{v}}}=0.4\) where R is the universal gas constant and ' \(\mathrm{C}_{\mathrm{v}}\) ' is molar specific heat at constant volume. The gas is made up of molecules which are
- A rigid diatomic.
- B monoatomic.
- C non-rigid diatomic.
- D polyatomic.
Answer & Solution
Correct Answer
(A) rigid diatomic.
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \text {Given: } \frac{R}{C_v}=0.4 \\
& C_V=\frac{R}{0.4}=\frac{5 R}{2} \\
& C_P=C_V+R \\
& \therefore \quad C_P=\frac{7 R}{2} \\
& \gamma=\frac{C_P}{C_v}=\frac{\frac{7}{2}}{\frac{5}{2}} \\
& \gamma=\frac{7}{5}
\end{aligned}\)
\(\therefore \quad\) The gas is made up of rigid diatomic molecules.
& \text {Given: } \frac{R}{C_v}=0.4 \\
& C_V=\frac{R}{0.4}=\frac{5 R}{2} \\
& C_P=C_V+R \\
& \therefore \quad C_P=\frac{7 R}{2} \\
& \gamma=\frac{C_P}{C_v}=\frac{\frac{7}{2}}{\frac{5}{2}} \\
& \gamma=\frac{7}{5}
\end{aligned}\)
\(\therefore \quad\) The gas is made up of rigid diatomic molecules.
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