MHT CET · Physics · Kinetic Theory of Gases
For a gas having ' \(\mathrm{X}\) ' degrees of freedom, ' \(\gamma\) ' is \(\left(\gamma=\right.\) ratio of specific heats \(\left.=C_{\mathrm{P}} / \mathrm{C}_{\mathrm{V}}\right)\)
- A \(\frac{1+X}{2}\)
- B \(1+\frac{X}{2}\)
- C \(1+\frac{2}{X}\)
- D \(1+\frac{1}{X}\)
Answer & Solution
Correct Answer
(C) \(1+\frac{2}{X}\)
Step-by-step Solution
Detailed explanation
\(\gamma\) and degrees of freedom is related by
\(\gamma=\frac{\mathrm{f}+2}{\mathrm{f}}\)
Where \(\mathrm{f}\) is the number of degrees of freedoms. Given \(\mathrm{f}=\mathrm{X}\),
\(\therefore \quad \gamma=\frac{X+2}{X}=1+\frac{2}{X}\)
\(\gamma=\frac{\mathrm{f}+2}{\mathrm{f}}\)
Where \(\mathrm{f}\) is the number of degrees of freedoms. Given \(\mathrm{f}=\mathrm{X}\),
\(\therefore \quad \gamma=\frac{X+2}{X}=1+\frac{2}{X}\)
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