MHT CET · Physics · Semiconductors
For a common emitter transistor, if \(\frac{\mathrm{I}_{\mathrm{C}}}{\mathrm{I}_{\mathrm{E}}}=0.95\), then the current gain is
- A \(47.5\)
- B \(44\)
- C \(19\)
- D \(15\)
Answer & Solution
Correct Answer
(C) \(19\)
Step-by-step Solution
Detailed explanation
\(\alpha = \frac{\mathrm{I}_{\mathrm{C}}}{\mathrm{I}_{\mathrm{E}}} = 0.95\) \(\beta = \frac{\alpha}{1 - \alpha}\)
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