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MHT CET · Physics · Dual Nature of Matter

Following graph shown the variation of stopping potential corresponding to the frequency of incident radiation \((v)\) for a given metal. The correct variation is shown in graph [ \(v_0=\) threshold frequency]

  1. A (C)
  2. B (B)
  3. C (A)
  4. D (D)
Verified Solution

Answer & Solution

Correct Answer

(C) (A)

Step-by-step Solution

Detailed explanation

Concept: Stopping potential \(V\) is related to the maximum kinetic energy \(K_{\max }\) of the photoelectrons, via Einstien's photo-electric effect relation:
\(e V=K_{\max }=h v-h v_0\)
Therefore,
\(V=\left(\frac{h}{e}\right) v-\left(\frac{h}{e}\right) v_0\)
Therefore, \(V\) vs \(v\) is straighline with positive slope and at \(v=v_0\) the stopping potential is zero.