MHT CET · Physics · Dual Nature of Matter
Following graph shown the variation of stopping potential corresponding to the frequency of incident radiation \((v)\) for a given metal. The correct variation is shown in graph [ \(v_0=\) threshold frequency]

- A (C)
- B (B)
- C (A)
- D (D)
Answer & Solution
Correct Answer
(C) (A)
Step-by-step Solution
Detailed explanation
Concept: Stopping potential \(V\) is related to the maximum kinetic energy \(K_{\max }\) of the photoelectrons, via Einstien's photo-electric effect relation:
\(e V=K_{\max }=h v-h v_0\)
Therefore,
\(V=\left(\frac{h}{e}\right) v-\left(\frac{h}{e}\right) v_0\)
Therefore, \(V\) vs \(v\) is straighline with positive slope and at \(v=v_0\) the stopping potential is zero.
\(e V=K_{\max }=h v-h v_0\)
Therefore,
\(V=\left(\frac{h}{e}\right) v-\left(\frac{h}{e}\right) v_0\)
Therefore, \(V\) vs \(v\) is straighline with positive slope and at \(v=v_0\) the stopping potential is zero.
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