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MHT CET · Physics · Waves and Sound

Find the wrong statement form the following about the equation of stationary wave given by Y=0.04cosπxsin50πt m where t is in second. Then for the stationary wave.

  1. A Time Period = 0.02s
  2. B Wavelength = 2 m
  3. C Velocity = 50 m/s
  4. D Amplitude = 0.02 m
Verified Solution

Answer & Solution

Correct Answer

(A) Time Period = 0.02s

Step-by-step Solution

Detailed explanation

Key Idea – The displacement of a wave in term of time period is given by
y=Asin2πtT-xλ
This equation in terms of speed of wave (v),
Becomes y=Asin2πλvt-x
The given equation of wave is
y=0.04cosπxsin50πt
=0.02sin50πt+πx+0.02sin50πt-πx
2sinA.cosB=sinA+B.cosA-B
Thus, the given wave is the combination of two waves,
y1=0.02sin50πt+πxin-vex-direction
and y2=0.02sin50πt-πx (in + ve x-direction)
Comparing them with the general equation of wave asinωt+kx , we get
Amplitude, a = 0.02m
Time period, T = 2π50π=125=0.04s
Wavelength, λ=2ππ=2m
Velocity, v = 50π×λ2π
=1002=50ms-1
So, option (a) is wrong.