MHT CET · Physics · Rotational Motion
Figure shows triangular lamina which can rotate about different axes. Moment of inertia is maximum, about the axis
- A PR
- B QS
- C QR
- D PQ
Answer & Solution
Correct Answer
(C) QR
Step-by-step Solution
Detailed explanation
The moment of inertia is given by
\(\mathrm{I}=\sum \mathrm{m}_{\mathrm{i}} \mathrm{r}_{\mathrm{i}}^2\)
If the distance of particles from the axis of rotation is larger, then the moment of inertia will be larger. For axis \(\mathrm{QR}\), the particles will be situated at greater distances and hence the moment of inertia will be greater.
\(\mathrm{I}=\sum \mathrm{m}_{\mathrm{i}} \mathrm{r}_{\mathrm{i}}^2\)
If the distance of particles from the axis of rotation is larger, then the moment of inertia will be larger. For axis \(\mathrm{QR}\), the particles will be situated at greater distances and hence the moment of inertia will be greater.
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