ExamBro
ExamBro
MHT CET · Physics · Capacitance

Energy per unit volume for a capacitor having area \(A\) and separation \(d\) kept at potential difference \(V\) is given by

  1. A \(\frac{1}{2} \varepsilon_{0} \frac{V^{2}}{d^{2}}\)
  2. B \(\frac{1}{2 \varepsilon_{0}} \frac{V^{2}}{d^{2}}\)
  3. C \(\frac{1}{2} C V^{2}\)
  4. D \(\frac{Q^{2}}{2 C}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{2} \varepsilon_{0} \frac{V^{2}}{d^{2}}\)

Step-by-step Solution

Detailed explanation

Energy density \(=\frac{1}{2} \varepsilon_{0} E^{2}\)
Since
\(E=\frac{V}{d}\)
Therefore energy \(=\frac{1}{2} \varepsilon_{0}\left(\frac{V^{2}}{d^{2}}\right)\)
Same subject
Explore more questions on app