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MHT CET · Physics · Dual Nature of Matter

Energy of the incident photons on the metal surface is initially 4 W and then 6 W where W is the work function of that metal. The ratio of velocities of emitted photoelectrons is

  1. A \(\sqrt{3}: \sqrt{5}\)
  2. B \(1: 2\)
  3. C \(2: 3\)
  4. D \(\sqrt{2}: \sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\sqrt{3}: \sqrt{5}\)

Step-by-step Solution

Detailed explanation

\(K_1 = E_1 - W = 4W - W = 3W\) \(K_2 = E_2 - W = 6W - W = 5W\)