MHT CET · Physics · Dual Nature of Matter
Energy of the incident photons on the metal surface is initially 4 W and then 6 W where W is the work function of that metal. The ratio of velocities of emitted photoelectrons is
- A \(\sqrt{3}: \sqrt{5}\)
- B \(1: 2\)
- C \(2: 3\)
- D \(\sqrt{2}: \sqrt{3}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{3}: \sqrt{5}\)
Step-by-step Solution
Detailed explanation
\(K_1 = E_1 - W = 4W - W = 3W\) \(K_2 = E_2 - W = 6W - W = 5W\)
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