MHT CET · Physics · Atomic Physics
Energy of electron in the second orbit of hydrogen atom is E. The energy of electron ' \(E_3\) ' in the third orbit of helium ( \(\left.\mathrm{He}\right)\) atom will be
- A \(E_3=\frac{4 E}{9}\)
- B \(E_3=\frac{16 E}{3}\)
- C \(E_3=\frac{16 E}{9}\)
- D \(E_3=\frac{4 E}{3}\)
Answer & Solution
Correct Answer
(A) \(E_3=\frac{4 E}{9}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{E} \propto \frac{1}{\mathrm{n}^2} \\ & \therefore \frac{\mathrm{E}_3}{\mathrm{E}_2}=\frac{4}{9} \\ & \therefore \mathrm{E}_3=\frac{4}{9} \mathrm{E}_2\end{aligned}\)
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