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MHT CET · Physics · Dual Nature of Matter

De-Broglie wavelength associated with an electron accelerated through a potential difference ' \(\mathrm{V}\) ' is ' \(\lambda\) '. When the accelerating potential is increased to ' \(4 \mathrm{~V}\) ', de-Broglie wavelength.

  1. A reduces to half
  2. B remains the same
  3. C reduces to \((1 / 4)^{\text {th }}\)
  4. D increases by \(25 \%\)
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Answer & Solution

Correct Answer

(A) reduces to half

Step-by-step Solution

Detailed explanation

De-Broglie wavelength, \(\lambda=\frac{1.228}{\sqrt{V}}(\mathrm{~nm})\)
If \(\mathrm{V}\) is increased to \(4 \mathrm{~V}\), then \(\lambda\) will become \(\frac{1}{\sqrt{4}}\) times or \(\frac{1}{2}\) times.
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