MHT CET · Physics · Capacitance
Consider the following circuit. By keeping \(S_1\) closed, the capacitor is fully charged and then \(S_1\) is opened and \(S_2\) is closed, then
- A At time \(t=0\), the energy stored in the circuit is purely in the form of magnetic energy.
- B At \(t\gt0\), there is no exchange of energy between L and C .
- C At any time \(t\gt0\), the current in the circuit is in the same direction.
- D At any time \(\mathrm{t}\gt0\), the instantaneous current in the circuit may be \(\mathrm{V} \sqrt{\frac{\mathrm{c}}{\mathrm{L}}}\)
Answer & Solution
Correct Answer
(D) At any time \(\mathrm{t}\gt0\), the instantaneous current in the circuit may be \(\mathrm{V} \sqrt{\frac{\mathrm{c}}{\mathrm{L}}}\)
Step-by-step Solution
Detailed explanation
Maximum energy in capacitor \(=\) Maximum energy in inductor
\(\frac{1}{2} \mathrm{CV}^2=\frac{1}{2} \mathrm{LI}^2\)
\(\begin{array}{ll}\therefore & I^2=\frac{C}{L} V^2 \\ \therefore I=V \sqrt{\frac{C}{L}}\end{array}\)
\(\frac{1}{2} \mathrm{CV}^2=\frac{1}{2} \mathrm{LI}^2\)
\(\begin{array}{ll}\therefore & I^2=\frac{C}{L} V^2 \\ \therefore I=V \sqrt{\frac{C}{L}}\end{array}\)
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