MHT CET · Physics · Current Electricity
Consider the circuit shown in the figure. The value of current ' \(I\) ' is
- A \(-\frac{7}{18} \mathrm{~A}\)
- B \(5 \mathrm{~A}\)
- C \(3 \mathrm{~A}\)
- D \(-3 \mathrm{~A}\)
Answer & Solution
Correct Answer
(A) \(-\frac{7}{18} \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Current from B to A, \(\mathrm{I}_1=\frac{6-(-8)}{28}=0.5 \mathrm{~A}\)
Current from \(\mathrm{C}\) to \(\mathrm{B}=\mathrm{I}_2=\frac{12-6}{54}=\frac{1}{9} \mathrm{~A}\)
Hence, \(\mathrm{I}=\mathrm{I}_2-\mathrm{I}_1=\frac{1}{9}-\frac{1}{2}=-\frac{7}{18} \mathrm{~A}\)
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