MHT CET · Physics · Electrostatics
Choose the correct relation between polarisation 'P' and electric susceptibility \(^{4} \chi_{e}{ }^{\prime}\) of dielectric material. \((\mathrm{E}=\) electric field \()\)
- A \(\mathrm{P}=\frac{\chi_{\mathrm{e}}}{\mathrm{E}^{2}}\)
- B \(\mathrm{P}=\frac{\chi_{\mathrm{e}}}{\mathrm{E}}\)
- C \(\mathrm{P}=\chi_{\mathrm{e}} \mathrm{E}\)
- D \(\mathrm{P}=\chi_{\mathrm{e}}^{2} \mathrm{E}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{P}=\chi_{\mathrm{e}} \mathrm{E}\)
Step-by-step Solution
Detailed explanation
\( \mathrm{P}=\chi_{\mathrm{e}} \mathrm{E} \)
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