MHT CET · Physics · Thermal Properties of Matter
Black bodies \(A\) and \(B\) radiate maximum energy with wavelength difference \(4 \mu \mathrm{~m}\). The absolute temperature of body \(A\) is 3 times that of B. The wavelength at which body B radiates maximum energy is
- A \(4 \mu \mathrm{~m}\)
- B \(6 \mu \mathrm{~m}\)
- C \(2 \mu \mathrm{~m}\)
- D \(8 \mu \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(6 \mu \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\lambda_A T_A = \lambda_B T_B\) \(\lambda_A (3 T_B) = \lambda_B T_B \Rightarrow 3 \lambda_A = \lambda_B\)
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