MHT CET · Physics · Gravitation
Binding energy of a revolving satellite at height h is \(3.5 \times 10^{8} \mathrm{~J}\). Its potential energy
is
- A \(7 \cdot 0 \times 10^{8} \mathrm{~J}\)
- B \(-7 \cdot 0 \times 10^{8} \mathrm{~J}\)
- C \(-3 \cdot 5 \times 10^{8} \mathrm{~J}\)
- D \(3.5 \times 10^{8} \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(-7 \cdot 0 \times 10^{8} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \text { Potential energy } &=-2(\text { Binding energy }) \\ &=-2 \times 3.5 \times 10^{8} \mathrm{~J} \\ &=-7.0 \times 10^{8} \mathrm{~J} \end{aligned}\)
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