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MHT CET · Physics · Electromagnetic Induction

At what rate a single conductor should cut the magnetic flux so that current of \(1.5 \mathrm{~mA}\) flows through it when a resistance of \(5 \Omega\) is connected across its ends?

  1. A \(6 \times 10^{-3} \frac{\mathrm{wb}}{\mathrm{s}}\)
  2. B \(8 \times 10^{-3} \frac{\mathrm{wb}}{\mathrm{s}}\)
  3. C \(4 \times 10^{-4} \frac{\mathrm{wb}}{\mathrm{s}}\)
  4. D \(7.5 \times 10^{-3} \frac{\mathrm{wb}}{\mathrm{s}}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(7.5 \times 10^{-3} \frac{\mathrm{wb}}{\mathrm{s}}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{I}=\frac{\mathrm{e}}{\mathrm{R}} \text { or } \mathrm{e}=\mathrm{IR} \\ & \mathrm{e}=\frac{\mathrm{d} \phi}{\mathrm{dt}} \therefore \frac{\mathrm{d} \phi}{\mathrm{dt}}=\mathrm{IR}=1.5 \times 10^{-3} \times 5 \\ & =7.5 \times 10^{-3} \mathrm{~Wb} / \mathrm{s}\end{aligned}\)