MHT CET · Physics · Kinetic Theory of Gases
At S.T.P., the mean free path of gas molecule is 1500 d , where 'd' is diameter of molecule. What will be the mean free path at 373 K at constant volume?
- A 1500 d
- B \(\frac{373}{273} \times 1500 \mathrm{~d}\)
- C \(\frac{273}{373} \times 1500 \mathrm{~d}\)
- D \(\sqrt{\frac{373}{273}} \times 1500 \mathrm{~d}\)
Answer & Solution
Correct Answer
(B) \(\frac{373}{273} \times 1500 \mathrm{~d}\)
Step-by-step Solution
Detailed explanation
\(\lambda = \frac{1}{\sqrt{2} \pi d^2 n}\) At constant volume, the number density \(n\) remains constant.
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