MHT CET · Physics · Thermodynamics
At constant temperature, the pressure of gas is decreased by \(20 \%\). The percentage change in volume
- A increase by \(29 \%\)
- B decreases by \(25 \%\)
- C increases by \(25 \%\)
- D decreases by \(20 \%\)
Answer & Solution
Correct Answer
(B) decreases by \(25 \%\)
Step-by-step Solution
Detailed explanation
Ideal gas equation states that: \(P V=n R T\)
As temperature remains constant, so \(P V=\) constant
As pressure decreases by \(20 \%\), so \(P_2=0.8 P\)
\(\begin{aligned} & \Rightarrow P V=(0.8 P) V_2 \\ & \Rightarrow V_2=\frac{P V}{0.8 P}=\frac{V}{0.8}=1.25 \mathrm{~V}\end{aligned}\)
So, volume of gas increase by \(25 \%\)
As temperature remains constant, so \(P V=\) constant
As pressure decreases by \(20 \%\), so \(P_2=0.8 P\)
\(\begin{aligned} & \Rightarrow P V=(0.8 P) V_2 \\ & \Rightarrow V_2=\frac{P V}{0.8 P}=\frac{V}{0.8}=1.25 \mathrm{~V}\end{aligned}\)
So, volume of gas increase by \(25 \%\)
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