MHT CET · Physics · Magnetic Effects of Current
At certain place a magnet makes 30 oscillations per minute. At another place if the magnetic induction is increased by two times the magnetic induction at first place, then the time period of same magnet will be
- A \(\frac{2}{\sqrt{3}} \mathrm{~s}\)
- B \(2 \sqrt{3} \mathrm{~s}\)
- C \(\frac{\sqrt{3}}{2} \mathrm{~s}\)
- D \(\quad \sqrt{3} \mathrm{~s}\)
Answer & Solution
Correct Answer
(A) \(\frac{2}{\sqrt{3}} \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
\(T=2 \pi \sqrt{\frac{I}{M B}} \Rightarrow T \propto \frac{1}{\sqrt{B}}\)
Given \(\mathrm{n}_1=30\) osc. \(/ \mathrm{min} \Rightarrow \mathrm{T}_1=2 \mathrm{~s}\)
\(\therefore \quad \frac{\mathrm{T}_2}{\mathrm{~T}_1}=\frac{\sqrt{\mathrm{B}_1}}{\sqrt{\mathrm{~B}_2}}\)
Now, \(\mathrm{B}_2=\mathrm{B}_1+2 \mathrm{~B}_1=3 \mathrm{~B}_1\)
\(\therefore \quad \frac{\mathrm{T}_2}{\mathrm{~T}_1}=\sqrt{\frac{\mathrm{B}_1}{3 \mathrm{~B}_1}}=\frac{1}{\sqrt{3}} \Rightarrow \mathrm{~T}_2=\frac{1}{\sqrt{3}} \times 2=\frac{2}{\sqrt{3}} \mathrm{~s}\)
Given \(\mathrm{n}_1=30\) osc. \(/ \mathrm{min} \Rightarrow \mathrm{T}_1=2 \mathrm{~s}\)
\(\therefore \quad \frac{\mathrm{T}_2}{\mathrm{~T}_1}=\frac{\sqrt{\mathrm{B}_1}}{\sqrt{\mathrm{~B}_2}}\)
Now, \(\mathrm{B}_2=\mathrm{B}_1+2 \mathrm{~B}_1=3 \mathrm{~B}_1\)
\(\therefore \quad \frac{\mathrm{T}_2}{\mathrm{~T}_1}=\sqrt{\frac{\mathrm{B}_1}{3 \mathrm{~B}_1}}=\frac{1}{\sqrt{3}} \Rightarrow \mathrm{~T}_2=\frac{1}{\sqrt{3}} \times 2=\frac{2}{\sqrt{3}} \mathrm{~s}\)
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