MHT CET · Physics · Ray Optics
Array of light is incident at an angle of incidence ' \(i\) ' on one surface of a prism of small angle \(\mathrm{A}\) and emerges normally from the other surface. If the refractive index of the material of the prism is ' \(\mu\) ', then the angle of incidence is equal to
- A \(\frac{\mathrm{A}}{2 \mu}\)
- B \(\frac{\mathrm{A} \mu}{2}\)
- C \(\mathrm{A} \mu\)
- D \(\frac{\mathrm{A}}{\mu}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{A} \mu\)
Step-by-step Solution
Detailed explanation
Given: \(\mathrm{e}=0\)
\(
\therefore \quad r_2=0, A=r_1
\)
Since ' \(\mathrm{i}\) ' is small, Snell's law of refraction can be modified to,
\(
\begin{aligned}
& \mu=\frac{i}{r_1} \\
\therefore \quad & i=\mu r_1=\mu A
\end{aligned}
\)
\(
\therefore \quad r_2=0, A=r_1
\)
Since ' \(\mathrm{i}\) ' is small, Snell's law of refraction can be modified to,
\(
\begin{aligned}
& \mu=\frac{i}{r_1} \\
\therefore \quad & i=\mu r_1=\mu A
\end{aligned}
\)
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