MHT CET · Physics · Oscillations
An object of mass 0.2 kg executes simple harmonic oscillations along the \(X\) - axis with frequency of \(\left(\frac{25}{\pi}\right) \mathrm{Hz}\). At the position \(x=0.04 \mathrm{~m}\), the object has kinetic energy 1 J and potential energy 0.6 J . The amplitude of oscillation is
- A 0.06 m
- B 0.6 m
- C 0.08 m
- D 0.8 m
Answer & Solution
Correct Answer
(C) 0.08 m
Step-by-step Solution
Detailed explanation
\(E = KE + PE = 1 \mathrm{~J} + 0.6 \mathrm{~J} = 1.6 \mathrm{~J}\) \(\omega = 2\pi f = 2\pi \left(\frac{25}{\pi}\right) \mathrm{rad/s} = 50 \mathrm{~rad/s}\)
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