MHT CET · Physics · Ray Optics
An ink mark is made on a piece of paper on which a glass slab of thickness ' \(t\) ' is placed. The ink mark appears to be raised up through a distance ' \(x\) ' when viewed at nearly normal incidence. If the refractive index of the material of glass slab is ' \(\mu\) ' then the thickness of glass slab is given by
- A \(\frac{\mu \mathrm{x}}{\mu-1}\)
- B \(\frac{(\mu-1)}{\mu}\)
- C \(\frac{\mu-1}{\mu \mathrm{x}}\)
- D \(\frac{\mu}{(\mu-1) x}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mu \mathrm{x}}{\mu-1}\)
Step-by-step Solution
Detailed explanation
Here, the normal shift is \(\mathrm{x}\) The formula for the normal shift is
\(
\begin{aligned}
x & =t\left(1-\frac{1}{\mu}\right) \\
t & =\frac{x}{\left(1-\frac{1}{\mu}\right)} \\
x & =t\left(1-\frac{1}{\mu}\right) \\
t & =\frac{x}{\left(1-\frac{1}{\mu}\right)} \\
\therefore \quad t & =\frac{x \mu}{(\mu-1)}
\end{aligned}
\)
\(
\begin{aligned}
x & =t\left(1-\frac{1}{\mu}\right) \\
t & =\frac{x}{\left(1-\frac{1}{\mu}\right)} \\
x & =t\left(1-\frac{1}{\mu}\right) \\
t & =\frac{x}{\left(1-\frac{1}{\mu}\right)} \\
\therefore \quad t & =\frac{x \mu}{(\mu-1)}
\end{aligned}
\)
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