MHT CET · Physics · Ray Optics
An ink mark is made on a piece of paper. A glass slab of thickness 't' is placed on it. The ink mark appears to be raised up through a distance ' \(x\) ' when viewed at nearly normal incidence. If the refractive index of material of glass slab is ' \(\mu\) ' then thickness of glass slab ' \(t\) ' is given by
- A \(\frac{(\mu-1)}{\mu \mathrm{x}}\).
- B \(\frac{\mu x}{(\mu-1)}\)
- C \(\frac{(\mu-1) x}{\mu}\)
- D \(\frac{\mu}{(\mu-1) x}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mu x}{(\mu-1)}\)
Step-by-step Solution
Detailed explanation
Here, the normal shift is x The formula for the normal shift is
\(\begin{aligned}
x & =t\left(1-\frac{1}{\mu}\right) \\
t & =\frac{x}{\left(1-\frac{1}{\mu}\right)} \\
\therefore \quad t & =\frac{\mu x}{(\mu-1)}
\end{aligned}\)
\(\begin{aligned}
x & =t\left(1-\frac{1}{\mu}\right) \\
t & =\frac{x}{\left(1-\frac{1}{\mu}\right)} \\
\therefore \quad t & =\frac{\mu x}{(\mu-1)}
\end{aligned}\)
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