MHT CET · Physics · Magnetic Effects of Current
An infinitely long straight conductor carrying current ' \(I\) ' is bent into a shape as shown in figure. The radius of the circular loop is ' \(r\) '. The magnetic induction at the centre of the loop at point ' \(o\) ' is
\(\text { ( } \mu_0=\text { permeability of free space) }\)
- A zero
- B \(\frac{\mu_0 \mathrm{I}}{4 \pi \mathrm{r}}(\pi-1)\)
- C \(\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{r}}(\pi+1)\)
- D \(\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{r}}(\pi-1)\)
Answer & Solution
Correct Answer
(D) \(\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{r}}(\pi-1)\)
Step-by-step Solution
Detailed explanation
\(B_{\text{left straight}} = \frac{\mu_0 I}{4 \pi r}\) (Out of page) \(B_{\text{right straight}} = \frac{\mu_0 I}{4 \pi r}\) (Out of page)
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