MHT CET · Physics · Rotational Motion
An inclined plane makes an angle \(30^{\circ}\) with the horizontal. A solid sphere rolling down an inclined plane from rest without slipping has linear acceleration ( \(g=\) acceleration due gravity) \(\left(\sin 30^{\circ}=0.5\right)\)
- A \(\frac{5 \mathrm{~g}}{7}\)
- B \(\frac{5 \mathrm{~g}}{14}\)
- C \(\frac{2 \mathrm{~g}}{3}\)
- D \(\frac{\mathrm{~g}}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{5 \mathrm{~g}}{14}\)
Step-by-step Solution
Detailed explanation
\(a = \frac{g \sin\theta}{1 + \frac{I}{MR^2}}\) \(a = \frac{g \sin 30^{\circ}}{1 + \frac{2}{5}}\)
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