MHT CET · Physics · Alternating Current

An ideal transformer converts $220 V$ AC to $3.3 kV$ AC. It transmits the power of $4.4 kW$ . If the primary coil has $600$ turns, then alternating current in the secondary coil is

A $\frac{1}{3} A$
B $\frac{4}{3} A$
C $\frac{5}{3} A$
D $\frac{7}{3} A$

Verified Solution

Answer & Solution

Correct Answer

(B) $\frac{4}{3} A$

Step-by-step Solution

Detailed explanation

V_{i n} = 220 V, V_{o u t} = 3.3 \times 10^{3} V

P o w e r = 4.4 k W

N_{p} = 600

P = V_{i n} \times I_{i n}

I_{i n} = \frac{4.4 \times 1000}{220} = \frac{44 \times 10}{22} = 20 A

\frac{e_{s}}{e_{p}} = \frac{I_{p}}{I_{s}}

I_{s} = I_{p} = \frac{e_{p}}{e_{s}} \times \frac{20 \times 220}{3.3 \times 1000} = \frac{44}{33} = \frac{4}{3} A

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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An ideal transformer converts 220 V AC to 3.3 kV AC. It transmits the power of 4.4 kW. If the primary coil has 600 turns, then alternating current in the secondary coil is

Step-by-step Solution

An ideal transformer converts $220 V$ AC to $3.3 kV$ AC. It transmits the power of $4.4 kW$ . If the primary coil has $600$ turns, then alternating current in the secondary coil is