MHT CET · Physics · Dual Nature of Matter
An excited hydrogen atom emits a photon of wavelength ' \(\lambda\) ' in returning to ground state. The quantum number ' \(n\) ' of the excited state is ( \(\mathrm{R}=\) Rydberg's constant)
- A \(\sqrt{\lambda \cdot R(\lambda R-1)}\)
- B \(\sqrt{\frac{\lambda \mathrm{R}}{(\lambda \mathrm{R}-1)}}\)
- C \(\sqrt{\frac{(\lambda \mathrm{R}-1)}{\lambda \mathrm{R}}}\)
- D \(\sqrt{\frac{1}{\lambda \mathrm{R}(\lambda \mathrm{R}-1)}}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{\frac{\lambda \mathrm{R}}{(\lambda \mathrm{R}-1)}}\)
Step-by-step Solution
Detailed explanation
Using Rydberg's formula
\(\frac{1}{\lambda}=\mathrm{R}\left[\frac{1}{1^2}-\frac{1}{\mathrm{n}^2}\right] \quad \ldots(\because \mathrm{m}=1)\)
\(\therefore \quad \frac{\mathrm{n}^2-1}{\mathrm{n}^2}=\frac{1}{\lambda \mathrm{R}} \Rightarrow 1-\frac{1}{\mathrm{n}^2}=\frac{1}{\lambda \mathrm{R}} \Rightarrow \frac{\lambda \mathrm{R}-1}{\lambda \mathrm{R}}=\frac{1}{\mathrm{n}^2}\)
\(\therefore \quad \mathrm{n}=\sqrt{\frac{\lambda \mathrm{R}}{\lambda \mathrm{R}-1}}\)
\(\frac{1}{\lambda}=\mathrm{R}\left[\frac{1}{1^2}-\frac{1}{\mathrm{n}^2}\right] \quad \ldots(\because \mathrm{m}=1)\)
\(\therefore \quad \frac{\mathrm{n}^2-1}{\mathrm{n}^2}=\frac{1}{\lambda \mathrm{R}} \Rightarrow 1-\frac{1}{\mathrm{n}^2}=\frac{1}{\lambda \mathrm{R}} \Rightarrow \frac{\lambda \mathrm{R}-1}{\lambda \mathrm{R}}=\frac{1}{\mathrm{n}^2}\)
\(\therefore \quad \mathrm{n}=\sqrt{\frac{\lambda \mathrm{R}}{\lambda \mathrm{R}-1}}\)
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