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MHT CET · Physics · Dual Nature of Matter

An excited hydrogen atom emits a photon of wavelength ' \(\lambda\) ' in returning to ground state. The quantum number ' \(n\) ' of the excited state is ( \(\mathrm{R}=\) Rydberg's constant)

  1. A \(\sqrt{\lambda \cdot R(\lambda R-1)}\)
  2. B \(\sqrt{\frac{\lambda \mathrm{R}}{(\lambda \mathrm{R}-1)}}\)
  3. C \(\sqrt{\frac{(\lambda \mathrm{R}-1)}{\lambda \mathrm{R}}}\)
  4. D \(\sqrt{\frac{1}{\lambda \mathrm{R}(\lambda \mathrm{R}-1)}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sqrt{\frac{\lambda \mathrm{R}}{(\lambda \mathrm{R}-1)}}\)

Step-by-step Solution

Detailed explanation

Using Rydberg's formula
\(\frac{1}{\lambda}=\mathrm{R}\left[\frac{1}{1^2}-\frac{1}{\mathrm{n}^2}\right] \quad \ldots(\because \mathrm{m}=1)\)
\(\therefore \quad \frac{\mathrm{n}^2-1}{\mathrm{n}^2}=\frac{1}{\lambda \mathrm{R}} \Rightarrow 1-\frac{1}{\mathrm{n}^2}=\frac{1}{\lambda \mathrm{R}} \Rightarrow \frac{\lambda \mathrm{R}-1}{\lambda \mathrm{R}}=\frac{1}{\mathrm{n}^2}\)
\(\therefore \quad \mathrm{n}=\sqrt{\frac{\lambda \mathrm{R}}{\lambda \mathrm{R}-1}}\)