MHT CET · Physics · Atomic Physics
An electron is moving in an orbit around the nucleus in an atom. Let \(m\), b orbital magnetic moment and \(L\) be angular momentum of the electron, then
- A \(m\) and \(L\) are in opposite direction perpendicular to the plane of orbit.
- B \(m\) and \(L\) are in opposite direction parallel to the plane of orbit.
- C \(m\) and \(L\) are in the same direction perpendicular to the plane of the orbit.
- D \(m\) and \(L\) are in the same direction parallel to plane of the orbit.
Answer & Solution
Correct Answer
(A) \(m\) and \(L\) are in opposite direction perpendicular to the plane of orbit.
Step-by-step Solution
Detailed explanation
Consider the following diagram:
The magnetic moment due to the movement of electron is given by,
\(\vec{m}=i \vec{A}\)
The direction of magnetic moment will be into the paper, using the right hand curl rule.
The angular momentum of electron is given by,
\(\vec{L}=\vec{r} \times \vec{p}\)
We know \(\vec{p}\) is along \(\vec{u}\) as shown in the figure, then
\(\vec{L}=m \vec{r} \times \vec{u}\)
The direction of angular momentum of the electron will be out of the plane of the paper.
The magnetic moment due to the movement of electron is given by,
\(\vec{m}=i \vec{A}\)
The direction of magnetic moment will be into the paper, using the right hand curl rule.
The angular momentum of electron is given by,
\(\vec{L}=\vec{r} \times \vec{p}\)
We know \(\vec{p}\) is along \(\vec{u}\) as shown in the figure, then
\(\vec{L}=m \vec{r} \times \vec{u}\)
The direction of angular momentum of the electron will be out of the plane of the paper.
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