MHT CET · Physics · Atomic Physics

An electron in stationary hydrogen atom jumps from \(4^{\text {th }}\) energy level to ground level. The velocity that the photon acquired as a result of electron transition will be ( \(h=\) Planck's constant, \(R=\) Rydberg's constant, \(m=\) mass of photon)

A \(\frac{11 R h}{16 m}\)
B \(\frac{15 R h}{16 m}\)
C \(\frac{9 R h}{16 m}\)
D \(\frac{13 R h}{16 m}\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{15 R h}{16 m}\)

Step-by-step Solution

Detailed explanation

The change in energy is given by
\(\Delta E=h c R\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)\)
Here, energy of photon, \(\Delta E=R h c\left(1-\frac{1}{4^2}\right)\)
\(\Rightarrow \Delta E=\frac{15}{16} R h c\)
Now, energy of photon \(=m c^2\)
\(\begin{aligned} & \Rightarrow m c^2=\frac{15}{16} R h c \\ & \Rightarrow c=\frac{15 R h}{16 m}\end{aligned}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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