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MHT CET · Physics · Magnetic Effects of Current

An electron (e) moves in circular orbit of radius ' \(r\) ' with uniform speed ' \(\mathrm{V}\) '. It produces magnetic field ' \(\mathrm{B}\) ' at the center of circle. The magnetic field \(B\) is ( \(\mu_0=\) permeability of free space)

  1. A \(\frac{\mu_0 \mathrm{e}}{4 \pi}\left(\frac{\mathrm{V}}{\mathrm{r}^2}\right)\)
  2. B \(\frac{\mu_0 \mathrm{e}}{4 \pi} \mathrm{Vr}^2\)
  3. C \(\frac{\mu_0 \mathrm{e}}{4 \pi}\left(\frac{\mathrm{V}}{\mathrm{r}}\right)\)
  4. D \(\frac{\mu_0 \mathrm{e}}{4 \pi} \mathrm{Vr}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\mu_0 \mathrm{e}}{4 \pi}\left(\frac{\mathrm{V}}{\mathrm{r}^2}\right)\)

Step-by-step Solution

Detailed explanation

Magnetic field at the center of a circular coil is given by
\(
\mathrm{B}=\frac{\mu_0 \mathrm{I}}{2 \mathrm{r}}
\)
In this case, the current \(\mathrm{I}=\frac{\mathrm{e}}{\mathrm{T}}=\frac{\mathrm{eV}}{2 \pi \mathrm{r}}\)
\(
\mathrm{B}=\frac{\mu_0 \mathrm{eV}}{4 \pi \mathrm{r}^2}
\)