MHT CET · Physics · Dual Nature of Matter
An electron accelerated by a potential difference 'V' has de-Broglie wavelength ' \(\lambda\) '. If the electron is accelerated by a potential difference ' 9 V ', its de-Broglie wavelength will be
- A \(\frac{\lambda}{4 \cdot 5}\)
- B \(\frac{\lambda}{3}\)
- C \(\frac{\lambda}{2}\)
- D \(\lambda\)
Answer & Solution
Correct Answer
(B) \(\frac{\lambda}{3}\)
Step-by-step Solution
Detailed explanation
\( \lambda = \frac{h}{\sqrt{2me V}} \) \( \lambda \propto \frac{1}{\sqrt{V}} \)
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