MHT CET · Physics · Current Electricity
An electrical circuit consists of the resistances \(R, r_1, R_2\) and voltage sources \(E_1\) and \(E_2\) as shown in the figure The correct equation for the loop \(E B C D E\) is

- A \(E_1-\left(I_1+I_2\right) R+I_2 r_2=0\)
- B \(E_1-\left(I_1+I_2\right) R-I_1 r_1=0\)
- C \(E_1-\left(I_1+I_2\right) R+I_1 r_1=0\)
- D \(E_2-I_2 r_2-E_1-I_1 r_1=0\)
Answer & Solution
Correct Answer
(B) \(E_1-\left(I_1+I_2\right) R-I_1 r_1=0\)
Step-by-step Solution
Detailed explanation
Consider the figure below:

Potential drop on moving along \(E B C D E\) :
\(\begin{aligned} & -I_1 r_1+E_2-\left(I_1+I_2\right) R=0 \\ & \Rightarrow E_2-\left(I_1+I_2\right) R-I_1 r_1=0\end{aligned}\)

Potential drop on moving along \(E B C D E\) :
\(\begin{aligned} & -I_1 r_1+E_2-\left(I_1+I_2\right) R=0 \\ & \Rightarrow E_2-\left(I_1+I_2\right) R-I_1 r_1=0\end{aligned}\)
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