MHT CET · Physics · Electrostatics
An electric dipole of moment \(\overrightarrow{\mathrm{p}}\). is lying along a uniform electric field \(\overrightarrow{\mathrm{E}} \cdot\) The work done in rotating the dipole through \(90^{\circ}\) is
\(\left[\sin 0^{\circ}=\cos 90^{\circ}=0, \cos 0^{\circ}=\sin 90^{\circ}=1\right]\)
- A \(\mathrm{pE}\)
- B \(\sqrt{2} \mathrm{pE}\)
- C \(\mathrm{pE} / 2\)
- D \(3 p \mathrm{p}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{pE}\)
Step-by-step Solution
Detailed explanation
Work done \(=\Delta \mathrm{pE}\)
\(\begin{aligned} & \mathrm{pE}=-\overrightarrow{\mathrm{p}} \overrightarrow{\mathrm{E}} \\ & \mathrm{pE}_{\mathrm{f}}=0 \\ & \mathrm{pE}_{\mathrm{i}}=-\mathrm{pE} \\ & \Delta \mathrm{pE}=\mathrm{pE}\end{aligned}\)
\(\begin{aligned} & \mathrm{pE}=-\overrightarrow{\mathrm{p}} \overrightarrow{\mathrm{E}} \\ & \mathrm{pE}_{\mathrm{f}}=0 \\ & \mathrm{pE}_{\mathrm{i}}=-\mathrm{pE} \\ & \Delta \mathrm{pE}=\mathrm{pE}\end{aligned}\)
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