MHT CET · Physics · Electrostatics
An electric dipole of length 2 cm is placed with its axis making an angle of \(60^{\circ}\) to a uniform electric field of \(10^{+5} \mathrm{~N} / \mathrm{C}\). If it experiences a torque of \(9 \sqrt{3} \mathrm{Nm}\), the magnitude of the charge on the dipole is \(\left(\sin 60^{\circ}=\frac{\sqrt{3}}{2}\right)\)
- A \(7 \times 10^{-3} \mathrm{C}\)
- B \(8 \times 10^{-3} \mathrm{C}\)
- C \(9 \times 10^{-3} \mathrm{C}\)
- D \(\frac{9}{2} \times 10^{-3} \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(9 \times 10^{-3} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(\tau = p E \sin\theta = (q \cdot 2a) E \sin\theta\) \(q = \frac{\tau}{(2a) E \sin\theta}\)
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