MHT CET · Physics · Alternating Current
An e.m.f. \(\mathrm{e}=\mathrm{E}_0 \cos \omega \mathrm{t}\) is applied to a circuit containing \(\mathrm{L}, \mathrm{C}\) and R in series where \(X_L=3 R\) and \(X_C=R\). The average power dissipated in the circuit is
- A \(\frac{E_0^2}{5 R}\)
- B \(\frac{E_0^2}{10 R}\)
- C \(\frac{E_0^2}{15 R}\)
- D \(\frac{E_0^2}{20 R}\)
Answer & Solution
Correct Answer
(B) \(\frac{E_0^2}{10 R}\)
Step-by-step Solution
Detailed explanation
\(X = X_L - X_C = 3R - R = 2R\) \(Z = \sqrt{R^2 + X^2} = \sqrt{R^2 + (2R)^2} = \sqrt{R^2 + 4R^2} = \sqrt{5R^2} = R\sqrt{5}\)
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