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MHT CET · Physics · Rotational Motion

An annular ring has mass 10 kg and inner and outer radii are 10 m and 5 m respectively. Its moment of inertia about an axis passing through its centre and perpendicular to its plane is

  1. A \(525 \mathrm{kgm}^2\)
  2. B \(625 \mathrm{kgm}^2\)
  3. C \(525 \mathrm{gcm}^2\)
  4. D \(625 \mathrm{gcm}^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(625 \mathrm{kgm}^2\)

Step-by-step Solution

Detailed explanation

Quantity for Mass
The moment of inertia of the annular ring is
\(\begin{aligned}
I & =\frac{1}{2} M\left(R_1^2+R_2^2\right) \\
& =\frac{10(100+25)}{2}=625 \mathrm{kgm}^2
\end{aligned}\)