MHT CET · Physics · Alternating Current
An alternating voltage of \(22 \mathrm{~V}\) is applied across an inductance coil of reactance \(11 \Omega\). If the inductance of the coil is \(0.07 \mathrm{H}\), the frequency of alternating voltage is
- A \(25 \mathrm{~Hz}\)
- B \(40 \mathrm{~Hz}\)
- C \(50 \mathrm{~Hz}\)
- D \(20 \mathrm{~Hz}\)
Answer & Solution
Correct Answer
(A) \(25 \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
The inductive reactance is
\(\begin{aligned}
& X_L=\omega L \\
& \omega=2 \pi f \\
& \therefore 2 \pi f L=X_L \\
& \Rightarrow f=\frac{X_L}{2 \pi L}=\frac{11}{2 \pi(0.07)} \mathrm{Hz}=25 \mathrm{~Hz}
\end{aligned}\)
\(\begin{aligned}
& X_L=\omega L \\
& \omega=2 \pi f \\
& \therefore 2 \pi f L=X_L \\
& \Rightarrow f=\frac{X_L}{2 \pi L}=\frac{11}{2 \pi(0.07)} \mathrm{Hz}=25 \mathrm{~Hz}
\end{aligned}\)
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