MHT CET · Physics · Alternating Current
An alternating voltage \(\mathrm{E}=100 \sqrt{2} \sin (50 \mathrm{t})\) is connected to a \(2 \mu \mathrm{F}\) capacitor through an a.c. ammeter. The ammeter reading will be
- A 10 mA
- B 5 mA
- C 20 mA
- D 30 mA
Answer & Solution
Correct Answer
(A) 10 mA
Step-by-step Solution
Detailed explanation
\(E_{rms} = \frac{100 \sqrt{2}}{\sqrt{2}} = 100 \, \text{V}\) \(X_C = \frac{1}{\omega C} = \frac{1}{50 \times 2 \times 10^{-6}} = \frac{1}{100 \times 10^{-6}} = 10^4 \, \Omega\)
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