MHT CET · Physics · Electrostatics
An air filled parallel plate capacitor has a uniform electric field 'E' in the space between the plates. If the distance between the plates is 'd' and area of each plate is ' \(A^{\prime}\), the energy stored in the capacitor is \(\left(\epsilon_{0}=\right.\) permittivity of free space)
- A \(\frac{1}{2} \in_{0} \mathrm{E}^{2} \mathrm{Ad}\)
- B \(\mathrm{E}^{2} \frac{\mathrm{Ad}}{\epsilon_{0}}\)
- C \(\frac{1}{2} \in_{0} \mathrm{E}^{2}\)
- D \(\mathrm{E}_{0} \mathrm{E} \mathrm{Ad}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2} \in_{0} \mathrm{E}^{2} \mathrm{Ad}\)
Step-by-step Solution
Detailed explanation
Energy per unit volume in an electric field is
\(U=\frac{1}{2} \epsilon_{\mathrm{o}} E^{2}\)
Volume of the space between the plates is \(=\mathrm{Ad}\)
\(\therefore\) Energy stored in the electric field \(=\frac{1}{2} \epsilon_{0} E^{2} \mathrm{Ad}\)
\(U=\frac{1}{2} \epsilon_{\mathrm{o}} E^{2}\)
Volume of the space between the plates is \(=\mathrm{Ad}\)
\(\therefore\) Energy stored in the electric field \(=\frac{1}{2} \epsilon_{0} E^{2} \mathrm{Ad}\)
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