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MHT CET · Physics · Alternating Current

An a.c. e.m.f. of peak value \(=230 \mathrm{~V}\) and frequency 50 Hz is connected to a circuit with \(\mathrm{R}=11.5 \Omega, \mathrm{~L}=2.5 \mathrm{H}\) and a capacitor all in series. The value of capacitance is ' C ' for the current in the circuit to be maximum. The value of C and maximum current are respectively ( \(\pi^2=10\) )

  1. A \(2 \mu \mathrm{F}, 10 \mathrm{~A}\)
  2. B \(4 \mu \mathrm{F}, 20 \mathrm{~A}\)
  3. C \(6 \mu \mathrm{F}, 10 \mathrm{~A}\)
  4. D \(8 \mu \mathrm{F}, 20 \mathrm{~A}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4 \mu \mathrm{F}, 20 \mathrm{~A}\)

Step-by-step Solution

Detailed explanation

\(C = \frac{1}{4\pi^2 f^2 L}\) \(C = \frac{1}{4 \times 10 \times (50)^2 \times 2.5} = \frac{1}{250000} = 4 \times 10^{-6} \mathrm{~F} = 4 \mu \mathrm{F}\)