MHT CET · Physics · Alternating Current
An a.c. circuit contains resistance of \(12 \Omega\) and inductor of inductive reactance \(5 \Omega\). The phase angle between current and potential difference will be
- A \(\sin ^{-1}\left(\frac{12}{13}\right)\)
- B \(\cos ^{-1}\left(\frac{5}{12}\right)\)
- C \(\sin ^{-1}\left(\frac{5}{12}\right)\)
- D \(\cos ^{-1}\left(\frac{12}{13}\right)\)
Answer & Solution
Correct Answer
(D) \(\cos ^{-1}\left(\frac{12}{13}\right)\)
Step-by-step Solution
Detailed explanation
\(Z = \sqrt{R^2 + X_L^2} = \sqrt{12^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13 \, \Omega\) \(\cos \phi = \frac{R}{Z} = \frac{12}{13}\)
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