MHT CET · Physics · Alternating Current
Alternating current of peak value \(\left(\frac{2}{\pi}\right)\) A flows through the primary coil of transformer. The coefficient of mutual inductance between primary and secondary coil is \(1 \mathrm{H}\). The peak e.m.f. induced in secondary coil is (Frequency of a.c. \(=50 \mathrm{~Hz}\) )
- A \(400 \mathrm{~V}\)
- B \(200 \mathrm{~V}\)
- C \(300 \mathrm{~V}\)
- D \(100 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(200 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Given \(: \mathrm{I}_{0}=\frac{2}{\pi}\) ampere \(v=50 \mathrm{~Hz} \mathrm{~L}=1 \mathrm{H}\)
Thus \(w=2 \pi v=2 \pi(50)=100 \pi\)
Alternating current flowing through the coil is given by \(I=I_{0} \sin w t\)
Differentiating it wr.t. time we get \(\frac{\mathrm{dI}}{\mathrm{dt}}=\mathrm{I}_{0} \mathrm{w} \cos w \mathrm{t}\) \(\left.\therefore \frac{\mathrm{dI}}{\mathrm{dt}}\right|_{\max }=\mathrm{I}_{0} \mathrm{~W}=\frac{2}{\pi} \times 100 \pi=200\) ampere per second
Peak e.m.f induced \(\mathcal{E}=\mathrm{L} \frac{\mathrm{dI}}{\mathrm{dt}}\)
\(\Longrightarrow \mathcal{E}=1 \times 200=200 \mathrm{~V}\
Thus \(w=2 \pi v=2 \pi(50)=100 \pi\)
Alternating current flowing through the coil is given by \(I=I_{0} \sin w t\)
Differentiating it wr.t. time we get \(\frac{\mathrm{dI}}{\mathrm{dt}}=\mathrm{I}_{0} \mathrm{w} \cos w \mathrm{t}\) \(\left.\therefore \frac{\mathrm{dI}}{\mathrm{dt}}\right|_{\max }=\mathrm{I}_{0} \mathrm{~W}=\frac{2}{\pi} \times 100 \pi=200\) ampere per second
Peak e.m.f induced \(\mathcal{E}=\mathrm{L} \frac{\mathrm{dI}}{\mathrm{dt}}\)
\(\Longrightarrow \mathcal{E}=1 \times 200=200 \mathrm{~V}\
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- When a system is taken from state ' \(a\) ' to state ' c ' along a path abc , it is found that \(\mathrm{Q}=80 \mathrm{cal}\) and \(\mathrm{W}=35 \mathrm{cal}\). Along path adc, \(\mathrm{Q}=65 \mathrm{cal}\) the work done W along path adc is
MHT CET 2024 Easy - Two plane mirrors are perpendicular to each other. A ray after suffering reflection from the two mirrors will beMHT CET 2007 Medium
- The viscous force between two liquid layers isMHT CET 2024 Easy
- A fluid of density ' \(\rho\) ' and viscosity ' \(\eta\) ' is flowing through a pipe of diameter ' \(d\) ', with a velocity ' \(v\) '. Reynold number isMHT CET 2023 Medium
- The truth table for the given logic circuit is
MHT CET 2024 Medium - Water is flowing through a horizontal pipe in stream line flow. At the narrowest part of the pipeMHT CET 2023 Easy
More PYQs from MHT CET
- For a common emitter transistor, if \(\frac{\mathrm{I}_{\mathrm{C}}}{\mathrm{I}_{\mathrm{E}}}=0.95\), then the current gain isMHT CET 2025 Easy
- If \(A=\left[\begin{array}{lll}1 & a & 3 \\ 1 & 1 & 5 \\ 2 & 4 & 7\end{array}\right]\) and \(A^{-1}=\left[\begin{array}{ccc}13 & 2 & -7 \\ -3 & b & 2 \\ -2 & 0 & 1\end{array}\right]\), then the values of \(a\) and \(b\) are respectivelyMHT CET 2022 Easy
- The area of the region bounded by the curve and the line is ________ square units.MHT CET 2019 Medium
- The direction cosines of the line, which is perpendicular to the lines with direction rations \(-1,2,2\) and \(0,2,1\), are respectivelyMHT CET 2022 Hard
- Out of the following statements, which one is 'NOT' correct in the case of a thermodynamic process?MHT CET 2022 Easy
- In Young's double slit experiment, the distance between the two coherent sources is ' d ' and the distance between the source and screen is ' D '. When the wavelength ( \(\lambda\) ) of light source used is \(\frac{d^2}{3 D}\), then \(n^{\text {th }}\) dark fringe is observed on the screen, exactly in front of one of the slits. The value of ' \(n\) ' isMHT CET 2024 Medium