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MHT CET · Physics · Electromagnetic Induction

Alternating current of peak value \(\left(\frac{2}{\pi}\right)\) A flows through the primary coil of a transformer. The coefficient of mutual inductance between primary and secondary coils is 1 H . The peak e.m.f. induced in secondary coil (Frequency of a.c. \(=50 \mathrm{~Hz}\) )

  1. A 50 V
  2. B 150 V
  3. C 100 V
  4. D 200 V
Verified Solution

Answer & Solution

Correct Answer

(D) 200 V

Step-by-step Solution

Detailed explanation

\(\begin{aligned}
& \omega=2 \pi v=2 \pi(50)=100 \pi \\
& I=I_0 \sin \omega t \\
& \frac{d I}{d t}=I_0 \omega \cos \omega t
\end{aligned}\)
Maximum value of \(\frac{\mathrm{dI}}{\mathrm{dt}}=\mathrm{I}_0 \omega\)
\(\begin{gathered}
=\frac{2}{\pi}(100 \pi)=200 \mathrm{~A} / \mathrm{S} \\
\mathrm{E}=\mathrm{L} \frac{\mathrm{dI}}{\mathrm{dt}}=1 \times 200=200 \mathrm{~V}
\end{gathered}\)