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MHT CET · Physics · Nuclear Physics

Activity of a radioactive sample decreases to \(\left(\frac{1}{3}\right)^{r d}\) of its original value in 3 days. Then in 9 days its activity reduces to

  1. A \(\left(\frac{1}{18}\right)\) of the original value
  2. B \(\left(\frac{1}{9}\right)\) of the original value
  3. C \(\left(\frac{1}{27}\right)\) of the original value
  4. D \(\left(\frac{1}{3}\right)\) of the original value
Verified Solution

Answer & Solution

Correct Answer

(C) \(\left(\frac{1}{27}\right)\) of the original value

Step-by-step Solution

Detailed explanation

Activity after time \(t\) given that half-life is \(T\) :
\(A=\frac{A_0}{2^{t / T}}\)
\(\frac{A_0}{3}=\frac{A_0}{2^{3 / T}}\)
Activity in 9 days,
\(A=\frac{A_0}{2^{t / T}}=\frac{A_0}{2^{9 / T}}=\frac{A_0}{\left(2^{3 / T}\right)^3}=\frac{A_0}{27}\)