MHT CET · Physics · Waves and Sound
A wire of length \(L\), diameter ' \(d\) ' density of material ' \(Q\) ' is under tension ' T ', having fundamental frequency of vibration \(\mathrm{n}_{\mathrm{A}}\). Another wire of length 2 L , tension 2 T , density 2 Q and diameter 3 d has fundamental frequency of vibration \(n_B\). The ratio \(n_B: n_A\) is
- A \(1: 2\)
- B \(1: 4\)
- C \(1: 6\)
- D \(1: 8\)
Answer & Solution
Correct Answer
(C) \(1: 6\)
Step-by-step Solution
Detailed explanation
\(n = \frac{1}{2L} \sqrt{\frac{T}{\mu}}\) \(\mu = \rho A = \rho \pi (\frac{d}{2})^2 = \rho \frac{\pi d^2}{4}\)
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