MHT CET · Physics · Magnetic Effects of Current
A wire of length ' \(L\) ' carries a current ' \(I\) '. If the wire is turned into a square coil of single turn, the maximum magnitude of the torque in a given magnetic field ( \(\overrightarrow{\mathrm{B}}\) ) is
- A \(\frac{\text { IBL }}{16}\)
- B \(\frac{\text { IBL }}{8}\)
- C \(\frac{\mathrm{IBL}^2}{8}\)
- D \(\frac{\mathrm{IBL}^2}{16}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{IBL}^2}{16}\)
Step-by-step Solution
Detailed explanation
\(s = \frac{L}{4}\) \(A = s^2 = \left(\frac{L}{4}\right)^2 = \frac{L^2}{16}\)
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