MHT CET · Physics · Mechanical Properties of Solids
A wire of length 'L' and radius ' \(\mathrm{r}\) ' is loaded with a weight ' \(\mathrm{Mg}\) '. If ' \(\mathrm{Y}\) ' and ' \(\sigma\) ' denote the Young's modulus and poisson's ratio of the material of the wire respectively, then the decrease in the radius of the wire \((\Delta \mathrm{r})\) is given by
- A \(\frac{\mathrm{MgY}}{\pi \mathrm{r} \sigma}\)
- B \(\frac{\mathrm{Mg} \sigma}{\pi \mathrm{rY}}\)
- C \(\frac{\sigma \pi \mathrm{r}}{\mathrm{MgY}}\)
- D \(\frac{\mathrm{Mgr}}{\sigma \pi \mathrm{Y}}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{Mg} \sigma}{\pi \mathrm{rY}}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T} = \frac{\mathrm{F}}{\mathrm{A}} = \frac{\mathrm{Mg}}{\pi \mathrm{r}^2}\) \(\frac{\Delta \mathrm{L}}{\mathrm{L}} = \frac{\mathrm{T}}{\mathrm{Y}} = \frac{\mathrm{Mg}}{\pi \mathrm{r}^2 \mathrm{Y}}\)
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